# How to Solve Work Problem Part 2

This is the second part of the **Solving Work Problems Series**. In the **previous post**, we have discussed in detail the concept behind how to solve work problems. In this post, we are going to learn more examples and solve more complicated problems.

**Problem 2**

A hose can fill a pool in 3 hours, while a smaller hose can fill it in 5 hours. If the hoses are opened together the same time, how many hours will they be able to fill the pool?

*Solution*

House A can fill the pool in 3 hours, so it can fill 1/3 of the pool in 1 hour.

House A can fill the pool in 5 hours, so it can fill 1/5 of the pool in 1 hour.

Together, they can fill 1/3 + 1/5 of the pool in 1 hour.

Let x be the number of hours to fill the pool. As we have done in the previous post, we set up the following equation (read the previous post for details). That is,

Multiplying both sides by 15, the least common denominator of 1/5 and 1/3, we have

This means that the two hoses will fill the pool in 15/8 or 1 and 7/8 hours.

**Problem 3**

Chloe and Diane are gown designers in a prestigious company. Chloe and Diane can embellish a gown in 4 hours. Chloe alone can do the same task in 6 hours. How long will Diane be able to do the same task if she were to work alone?

*Solution*

Chloe and Diane can finish the task in 4 hours, so they can finish 1/4 of the task in 1 hour.

Chloe alone can finish the task in 6 hours, so she can finish 1/6 of the task in 1 hour.

Diane can finish the task in *x* hours, so she can finish 1/*x* of the task in 1 hour.

Note that if we combine the work of Chloe (1/6) and Diane (1/*x*), their rate is 1/4 of the task. That is

We multiply the equation by 24*x*, the **least common denominator** of 6, 4, and *x*, we have

This means that Diane can finish the task alone in 12 hours.

In the next post, we will have more examples.