This is the second part of a series of post on Solving Ratio Problems. In the first part, we have learned how to solve intuitively and algebraically problems involving ratio of two quantities. In this post, we are going to learn how to solve a ratio problem involving 3 quantities.
The ratio of the red, green, and blue balls in a box is 2:3:1. If there are 36 balls in the box, how many green balls are there?
Solution and Explanation
From the previous, post we have already learned the algebraic solutions of problems like the one shown above. So, we can have the following:
Let be the number of grous of balls per color.
So, there are 6 groups. Now, since we are looking for the number of green balls, we multiply x by 3.
So, there are 6 groups (3 green balls per group) = 18 green balls.
From above, is the number of blue balls. The expression 2x represent the number of red balls, so we have 2x = 2(6) = 12 balls. Therefore, we have 12 red balls, 18 green balls, and 6 blue balls.
We can check by adding them: 12 + 18 + 6 = 36.
This satisfies the condition above that there are 36 balls in all. Therefore, we are correct.