This is the third part of the Solving Age Problems Series. In this part, we will solve age problems with a variety of formats and difficulty that are not discussed in the first two parts. We have already solved six problems in the first and second part, so we start with the seventh problem.
Bill is four times as old as Carol. One fifth of Bill’s age added to one half Carol’s age is equal to years. How old are both of them?
Bill is older than Carol and he is four times older. This means that if Carol is years old, then Bill is years old. Now, one fifth of Bill’s age is and one half of Carol’s age is . Add these together and you get . Now, we have an equation. » Read more
This is the second part of the Solving Age Problem Series. We will continue solving age problems that are slightly more complicated that the first part. We have already discussed 3 problems in the first part of this series, so we continue with the fourth problem.
Simon is four years older than Jim. The sum of their ages is 52. How old is Simon?
This problem is a sort of review of first part of this series. Simon is older than Jim by years. So, if Jim is years old, then Simon is years old. The sum of their ages is . This means that if add and , then the sum is . That is the equation. » Read more
After a series of tutorials on word problems involving numbers, we now move to learning on how to solve word problems involving age. Age problems are very similar to number problems, so if you have finished reading The Number Word Problem Series, then it will be easier for you to solve the following age problems.
Benjie is thrice as old as his son Cedric. The sum of their ages is 64. How old are both of them?
This is one of those age problems that are very similar to number problems. Let’s take a specific case. If Cedric is say years old, then Benji is years old. This means that if Cedric is years old, then Benjie is . If we add their ages, the result is . » Read more