This is the third part of the Solving Consecutive Number Problems Series. In this post, we solve more problems about consecutive numbers. We have already discussed four problems in the first part and second part of this series, so we start with the fifth example.
There are 3 consecutive odd numbers. Twice the smallest number is one more than the largest. What are the numbers?
In the first post in this series, we have learned that odd numbers increase by 3 (e.g. 7, 9, and 11). So, let
= the smallest odd number
= the second odd number
= the largest odd number. Continue Reading