How to Solve Age Problems Part 1
After a series of tutorials on word problems involving numbers, we now move to learning on how to solve word problems involving age. Age problems are very similar to number problems, so if you have finished reading The Number Word Problem Series, then it will be easier for you to solve the following age problems.
Example 1
Benjie is thrice as old as his son Cedric. The sum of their ages is 64. How old are both of them?
Scratch Work
This is one of those age problems that are very similar to number problems. Let’s take a specific case. If Cedric is say years old, then Benji is
years old. This means that if Cedric is
years old, then Benjie is
. If we add their ages, the result is
.
Solution
Let be the age of Cedric and
be the age of Benjie.
Cedric’s Age + Benjie’s Age = 64
.
Dividing both sides of the equation by gives us
.
Therefore, Cedric is and Benjie is
year sold.
Check
is thrice
and
. So, we are correct.
Example 2
Karen is years older than Nina. Five years from now, the sum of their ages will be
. How old are both of them?
Scratch Work
If Nina is years old, then Karen is
years older, so her age will be
. Five years from now, both of their ages will increase by
as shown on the table below.
Therefore, 5 years from now, the sum of their ages will be equal to
. Now this sum is equal to
.
Solution
Let be Nina’s age and
be Karen’s age. In 5 years, Nina will be
years old and Karen will be
years old.
Now,
Subtracting from both sides of the equation, we have
Dividing both sides by we have
.
This means that Nina is and Karen is
.
Check
is 6 more than
and five years from now,
. Therefore, we are correct.
Example 3
Sarah is twice as old as Jimmy. Three years ago, the sum of their ages is 39. How old are both of them now?
Scratch Work
If Jimmy is years old, then Sarah’s age is twice his age, so Sarah is
years old. Three years ago, both are younger by
years, so both their ages must be subtracted by
.
Three years ago, the sum of their ages is . So, we add
and
and equate it to
Solution
Let be Jimmy’s age and
be Sarah’s age.
Three years ago, Jimmy was years old and Sarah was
years old.
Three years ago, the sum of Jimmy’s and Sarah’s age is
.
Adding to both sides of the equation results to
Dividing both sides by , we have
.
So, Jimmy is and Sarah is
.
Check
Three years ago, Jimmy was years old and Sarah was
years old. The sum of their ages was
.
That’s all for now, we discuss more problems in the next post.