In the previous post, we have learned why the **area of a parallelogram** is the product of its base and height. In this post, we are going to discuss a few problems involving base, height, and area of parallelograms.

**Example 1**

Find the area of a parallelogram whose base is 12 cm and whose height is 18 cm.

*Solution*

Area = base × height

Area = 12 cm × 18 cm

Area = 216 sq. cm.

**Be Careful**! Note that when we talk about area, we are talking about square units. You must be careful with this because the choices in the exam can have both 216 cm and 216 sq. com.

**Example 2**

Find the height of a parallelogram whose area is 30 cm and whose base is 8 cm.

*Solution*

If we let area be , base be and height be , then

Since we are looking for , we want leave it on the right hand side. Therefore, we divide both sides of the **equation** by 8 cm.

So,

Therefore, cm.

**Example 3**

*Solution*

What is the height of a parallelogram with area 8.5 m and base 4 m?

Since we are looking for in the equation, we divide both sides by 4.

Therefore,

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