# Week 10 Review: Answers and Solutions

After learning how to **solve motion problems**, let’s answer some exercises and problems. In the solutions, we let d = distance, r = rate, and t = time.

**Exercises**

1.) A car travels and average speed of 75 kph. If it traveled for 3.5 hours, what is the total distance traveled?

d = rt

d = (75 kph)(3.5 hrs) =

d = 262.5 km

2.) A bus traveled 4 hours from City A to City B which is 450 kilometers apart. What is its average speed?

d = rt

450 km = (4 hrs)(r)

r = (450 kph)/(4 hrs)

r = 112.5 km

**Problem**

1.) Two cars left City A at 8:00 am going to City B using the same route. Car 1 traveled at the average speed of 60 kph while Car 2 traveled at an average speed of 50kph. At what time were the two cars 25 kilometers apart?

Let x = time traveled by the two cars

60x – 50x = 25

10x = 25

x = 25/10

x = 2.5 hours

2.5 hours = 2hours and 30 mins

2 hours and 30 minutes after 8:00 am is 10:30 am.

Answer: 10:30 AM

2.) The road distance from Sapiro City to Lireo City is 195 km. Car 1 left Sapiro City going to Lireo City at an average speed of 70kph. Car 2 left City Lireo City going to Sapiro City at an average speed of 60 kph. If both cars left the two cities at the same time and use the same road, after how many hours will the two cars meet?

Car 1

Rate = 70kph

Time = x

Distance = 70x

Car 2

Rate = 60kph

Time = x

Distance = 60x

Total distance = 195kph

70x + 60x = 195

130x = 195

x = 195/130

x = 1.5hrs

3.) A red car left Vigan at 9:00 AM and traveled to Manila at an average speed of 45 kph. After one hour, a white car left the same place for Manila using the same route at an average speed of 60 kph. At what time will the white car overtake the red car?

RED CAR

Rate = 45kph

Time = x+1

Distance = 45(x+1)

WHITE CAR

Rage = 60kph

Time = x

Distance = 60x

60x = 45(x+1)

60x = 45x+45

60x – 45x = 45

15x = 45

x = 45/15

x = 3hours

3 hours after 10:00am is 1:00 p.m.

Note: We add 3 hours to 10:00 am because the second car left at 10:00 am.

Answer: 1:00pm noon

4.) Two cars started from the same point, at 12nn, traveling to opposite directions at 50 and 60 kph, respectively. What is the distance between them at exactly 3:30 PM?

CAR 1

Rate = 50kph

Time = 3.5 hrs

Distance = (50 kph)(3.5 hrs) = 175

CAR 2

Rate = 60kph

Time = 3.5 hrs

Distance = (60 kph)( 3.5 hrs) = 210

What is the distance between them at exactly 3:30 PM?

175 km + 210 km = 385 km

5.) Two cars from the same point traveling to opposite directions at 75 and 85 kph, respectively. After how many hours will they be 240 kilometers apart?

75x + 85x = 240

160x = 240

240/160 = x

x = 1.5 hours

6.) A blue car leaves City A for City B at exactly 8:00 AM traveling at average speed of 55 kph. A gray car leaves City B for City A at the same time traveling at an average speed of 45 kph. The distance between the two cities is 75 kilometers.

If the two cars use the same route, what time will they pass each other?

let x be the time

d = r x t

sum of the distance traveled by 2 cars is equal to 75km

so

55x + 45x = 75

100x = 75

x = 75/100 or 0.75 hours

0.75 hours (45 mins)

They will pass each other 45 mins after 8:00am so the answer is 8:45 am.

Answer: 8:45 am

Enjoy!

#3. I think 1:00 PM is the answer . your base time is 10AM dahil nag x+1 ka na sa red car. kahit manual computation by table. in 12PM 135km na na-travel ng red car but 120km pa lang sa white car. In 1PM 180km for red car then 180 sa white car

YOu are correct. I already edited the solution.

Thanks for pointing out the error.

#4. 385 KM. You said 175 km + 210 km = 285 km??? Its 385km

Thanks for pointing out the typo error. I changed it already.